Sec 1 Maths · Chapter 12

Perimeter and Area of Plane Figures

Learn to measure the distance around a shape and the space inside it. Revise unit conversions, rectangles, triangles, circles, compound figures, parallelograms and trapeziums.

Step-by-step explanations, clear diagrams, short self-checks and two free printable practice PDFs with worked solutions. No sign-up required.

Secondary 1 Mathematics Chapter 12 illustrated guide to perimeter and area of plane figures
Learning goals

What you will learn in Chapter 12

1

Convert units

Change between cm, m, km and their square units correctly.

2

Find perimeter and area

Choose the correct formula for rectangles, triangles and circles.

3

Solve compound shapes

Combine or subtract areas and trace the actual outside boundary.

4

Use perpendicular height

Calculate areas of parallelograms and trapeziums, including missing lengths.

Remember: unless a question says otherwise, both downloadable Chapter 12 PDFs use π = 3.142. Diagrams are schematic; use the measurements shown.

Jump to a lesson

12.1 · Conversion of Units

Length and area units are not converted the same way

Perimeter is a length, so its unit is cm, m or km. Area measures a surface, so its unit is cm², m² or km². When changing area units, square the length conversion factor.

Length

1 m = 100 cm
1 km = 1,000 m

Example: 4.35 m = 4.35 × 100 = 435 cm.

Area

1 m² = 10,000 cm²
1 cm² = 100 mm²
1 km² = 1,000,000 m²

Example: 0.072 m² = 0.072 × 10,000 = 720 cm².

A one-metre square has sides of 100 centimetres, so its area is 10,000 square centimetres. 100 cm100 cm 1 m²= 10,000 cm² 100 × 100= 10,000
Common mistake: 1 m² is not 100 cm². Both side lengths change by a factor of 100, so the area changes by 100 × 100.
12.2 · Basic Plane Figures

Perimeter goes around. Area fills the inside.

To find perimeter, add lengths along the boundary. To find area, measure how much surface a shape covers. These are different quantities and need different units.

Rectangle

Rectangle with length 10 centimetres and width 6 centimetres 10 cm6 cm 60 cm²

P = 2(l + w) A = lw

Perimeter = 2(10 + 6) = 32 cm
Area = 10 × 6 = 60 cm²

Square

Square with side length 8 centimetres 8 cm8 cm 64 cm²

P = 4s A = s²

Perimeter = 4 × 8 = 32 cm
Area = 8² = 64 cm²

ShapePerimeter / circumferenceArea
Rectangle2(l + w)lw
Square4ss²
TriangleSum of three side lengths½ × base × perpendicular height
Circle2πr = πdπr²
Parallelogram2(a + b), where a and b are adjacent sidesbase × perpendicular height
TrapeziumSum of all four side lengths½ × (sum of parallel sides) × perpendicular height
Reverse question tip: If a rectangle’s area and length are known, divide area by length to find its width. If a square’s area is known, take the square root to find its side.
12.2 · Triangles

Use the perpendicular height—not just any sloping side

Area = ½ × base × height

The height must be at 90° to the chosen base. The perimeter is found separately by adding the three sides.

Example: base = 12 cm and perpendicular height = 7 cm.

Area = ½ × 12 × 7 = 42 cm²

For a separate triangle with sides of 10 cm, 11 cm and 12 cm, its perimeter is 10 + 11 + 12 = 33 cm.

Triangle with a 12-centimetre base, a perpendicular height of 7 centimetres and a right-angle marker 7 cm12 cm
Schematic: labels take precedence over scale.
Worked example: find a missing height

A triangle has area 63 cm² and base 18 cm. Find its perpendicular height.

63 = ½ × 18 × h = 9h, so h = 7 cm.

12.2 · Circles and Semicircles

Radius, diameter, circumference and area

Circle

Circle of radius 7 centimetres, with centre O and a line from centre to circumference O7 cm

C = 2πr = πd

A = πr²

For r = 7 cm and π = 3.142:

C = 2 × 3.142 × 7 = 43.988 ≈ 44.0 cm (3 s.f.)
A = 3.142 × 7² = 153.958 ≈ 154 cm² (3 s.f.)

Semicircle

Semicircle of radius 4 centimetres and diameter 8 centimetres, including the straight edge 4 cm8 cm

A = ½πr²

P = πr + 2r

For r = 4 cm:

Area = ½ × 3.142 × 4² = 25.136 cm²
Complete perimeter = 3.142 × 4 + 8 = 20.568 cm.

Watch out: a semicircle’s complete perimeter includes the curved half-circumference and the straight diameter. Its area is simply half the circle’s area.
12.2 · Compound and Shaded Figures

Add parts, subtract gaps and trace the outside edge

Compound shapes combine simple figures. For area, divide the shape into manageable pieces or subtract an unwanted region. For perimeter, measure only the actual outside boundary.

1

Sketch and label

Mark all given lengths. Work out any missing dimensions.

2

Choose the area method

Add non-overlapping areas or subtract an opening from a larger figure.

3

Trace the perimeter

Count outer straight and curved edges only; ignore internal joins.

Example A · Corner removed

Ten by eight centimetre rectangle with a four by three centimetre top-right corner removed 10 cm (original) 8 cm 4 cm 3 cm
Not to scale. Dashed lines show the removed corner.

Area = 10 × 8 − 4 × 3 = 68 cm².

The two removed outer lengths are replaced by two equal inner lengths, so perimeter remains 36 cm.

Example B · Path outside a lawn

Uniform 2-metre-wide path around a 13 by 5 metre rectangular field, giving outer dimensions 17 by 9 metres 17 m (outer) 13 m × 5 m lawn 9 m 2 m path

Outer area = 17 × 9 = 153 m².
Inner area = 13 × 5 = 65 m².

Path area = 153 − 65 = 88 m².

When a circle is removed from a rectangle or square, the shaded area is often “rectangle or square area − circle area”. When a semicircle is attached, the shared straight edge usually does not belong to the outside perimeter.
12.3 · Parallelograms

A parallelogram uses a perpendicular height

Area = base × perpendicular height

Perimeter = 2(a + b)

For a base of 10 cm and perpendicular height of 6 cm:

Area = 10 × 6 = 60 cm²

The sloping side is not the height. If the same parallelogram has area 84 cm² and you choose a 12 cm side as the base, its corresponding height is 84 ÷ 12 = 7 cm.

Parallelogram with 10 centimetre horizontal base and 6 centimetre perpendicular height marked by a dashed line and right angle 10 cm 6 cm slopingside
12.4 · Trapeziums

Add the parallel sides before multiplying by height

Area = ½ × (a + b) × h

Here, a and b are the lengths of the two parallel sides, while h is the perpendicular distance between them.

Example: parallel sides = 8 cm and 14 cm; height = 5 cm.

A = ½ × (8 + 14) × 5 = 55 cm²

Worked example: missing parallel side

Area = 96 cm², height = 8 cm, one parallel side = 10 cm. Let the other side be x.

96 = ½ × (10 + x) × 8
96 = 4(10 + x)
24 = 10 + x
x = 14 cm

Trapezium with parallel sides 8 and 14 centimetres and perpendicular height 5 centimetres 8 cm 14 cm 5 cm
The two horizontal sides are parallel.
Common mistake: do not substitute a sloping side for the height. The formula uses the perpendicular distance between the parallel sides.
Worked examples

Apply the ideas to multi-step problems

Example 1 · Find dimensions from perimeter

A rectangle has perimeter 58 m. Its length is 7 m longer than its width. Find its area.

Reveal full working

Let width = x m and length = (x + 7) m.

2[x + (x + 7)] = 58
4x + 14 = 58
x = 11

Width = 11 m, length = 18 m.
Area = 11 × 18 = 198 m².

Example 2 · Area outside a circle

A circle of radius 5 cm lies inside a square of side 12 cm. Find the area outside the circle but inside the square, to 3 significant figures.

Reveal full working

Square = 12² = 144 cm².
Circle = 3.142 × 5² = 78.55 cm².

Required area = 144 − 78.55 = 65.45 cm².
65.5 cm² (3 s.f.).

Example 3 · Missing parallelogram height

A parallelogram has area 154 cm² and base 14 cm. Find its perpendicular height.

Reveal full working

Area = base × height.
154 = 14 × h
h = 154 ÷ 14 = 11 cm.

Example 4 · Shaded circular region

A square garden has side 14 m and a circular flowerbed of radius 5 m. Find the uncovered area to 3 significant figures.

Reveal full working

Square area = 14² = 196 m².
Circle area = 3.142 × 5² = 78.55 m².

Uncovered area = 196 − 78.55 = 117.45 m² ≈ 117 m² (3 s.f.).

Exam technique

Five mistakes to avoid

1. Mixing length and area units

Perimeter: cm or m. Area: cm² or m². Convert measurements before applying formulas.

2. Using a sloping height

Triangles, parallelograms and trapeziums require a height at 90° to the chosen base.

3. Forgetting the diameter

Complete perimeter of a semicircle is πr + 2r, not just πr.

4. Counting hidden/internal edges

A shared joining edge is not part of the outside perimeter of a combined shape.

5. Rounding too early

Keep accurate intermediate values, then round the final answer as required.

Before submitting

Show formula → substitution → calculation → correct unit. Check that your answer is reasonable.

Interactive self-check

Can you answer these six questions?

Choose one answer for each question, then select Check answers. Explanations appear after checking. Nothing is sent or stored.

1. Convert 0.15 m² into cm².
0.15 × 10,000 = 1,500 cm².
2. A rectangle measures 9 cm by 4 cm. What is its perimeter?
P = 2(9 + 4) = 26 cm. 36 cm² would be the area.
3. A triangle has base 14 cm and perpendicular height 6 cm. Find its area.
A = ½ × 14 × 6 = 42 cm².
4. A circle has diameter 10 cm. What is its radius?
Radius = diameter ÷ 2 = 5 cm.
5. A parallelogram has base 12 cm and perpendicular height 8 cm. Find its area.
A = 12 × 8 = 96 cm². Do not halve the parallelogram area.
6. A trapezium has parallel sides 6 cm and 10 cm, and height 4 cm. Find its area.
A = ½ × (6 + 10) × 4 = 32 cm².

Your score will appear here.

Diagnostic practice

Try these before opening the worksheets

Write down your working, then reveal the answers to check your reasoning.

Question A · Unit conversion

Convert 4,200 cm² to m².

Show answer
4,200 ÷ 10,000 = 0.42 m².

Question B · Semicircle

A semicircle has radius 3 cm. Find its complete perimeter, using π = 3.142.

Show answer
P = πr + 2r = 3.142 × 3 + 6 = 15.426 cm.

Question C · Compound area

Remove a 3 cm × 2 cm rectangle from a 12 cm × 7 cm rectangle. Find the remaining area.

Show answer
12 × 7 − 3 × 2 = 84 − 6 = 78 cm².

Question D · Trapezium

A trapezium has area 84 cm², height 7 cm and one parallel side 10 cm. Find the other parallel side.

Show answer
84 = ½(10 + x)7, so 24 = 10 + x; x = 14 cm.
Free PDF practice · No sign-up

Download Chapter 12 worksheets with worked solutions

Use the learning workbook to revise each topic first, then attempt the supplementary practice for more challenging, multi-step questions. Both resources are free to open, save and print.

PDF 1 · Learning workbook

Perimeter and Area — Chapter Workbook

Concept explanations, formulas, labelled diagrams, worked examples, topic-by-topic practice, mixed challenge questions and solutions.

Recommended first: learn → practise → review answers.

Open Free Workbook PDF ↗
PDF 2 · Supplementary practice

Additional Questions with Full Worked Solutions

Further questions on unit conversions, circles, shaded regions, paths, parallelograms, trapeziums and challenging compound figures.

Recommended next: attempt independently before reading the solutions.

Open Supplementary PDF ↗
Study tip: For every question, identify what is being measured, draw or annotate the figure, write the correct formula and give your answer with the proper unit. Check the worked solutions only after trying.
For students, parents and teachers

A simple Chapter 12 learning sequence

  1. Revise units first: distinguish length conversions from area conversions.
  2. Learn the basic formulas: rectangle, square, triangle and circle.
  3. Practise reasoning about boundaries: trace the outside of compound figures and identify excluded regions.
  4. Focus on perpendicular height: apply it to triangles, parallelograms and trapeziums.
  5. Work through PDF 1: complete topic practice before checking worked solutions.
  6. Use PDF 2 for extension: attempt its multi-step and shaded-region questions.
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